Question

8. A face 8N acting at angle 45° with horizontal find
the magnitude of its horizontal and vertically components​

Answer 1

Explanation:

Horizontal component of F is

FH=Fcos45∘=(8)(21)=42N

and vertical component of F is 

Fv=Fsin45∘=(8)(21)=42.N

mark me as brainlist

plz be my follower

Answer 2

Explanation:

$\\ f \cos( 45) = 8 \times 1 \div \sqrt{2} \\ = 8 \div \sqrt{2} = 4 \sqrt{2}$

hence the horizontal component is 4√2.

$f \sin(45) = 8 \times 1 \div \sqrt{2} \\ = 8 \div \sqrt{2} = 4 \sqrt{2}$

hence the vertical component is 4√2