Question

8. A floor which measures 15 m X 8 m is to be laid with tiles measuring 50 cm by 25 cm. Find the number of tiles required. Further, if a carpet is laid on the floor so that a space of l m exists between its edges and the edges of the floor, what fraction of the floor is uncovered ?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Area of floor = 15*8 = 120$m^{2}$

Area of 1 tile = 50cm*25cm = 0.5m*0.25m = 0.125$m^{2}$

No: of tiles required = Area of floor / Area of 1 tile = 120/0.125 = 960

Area of Carpet = 13m * 6m = 78$m^{2}$

Area uncovered = 120 - 78 = 42$m^{2}$

Fraction uncovered = 42/120 = 7/20