Question

b=3 , c =5 pythagoras theorem in notebook please dont report​

Answer 1

Answer:

$3^{2} + 4^{2} = 5^{2}$

Step-by-step explanation:

Pythagorean triplet formula.

a = $m^{2} - 1$

b = $2m$

c = $m^{2} + 1$

So, lets take

= 5 = $m^{2} + 1$

= 5 - 1 = $m^{2}$

= 4 = $m^{2}$

= 2 = m

Since, we have m = 2,

a = $m^{2} - 1$

  = $2^{2} -1$

  = 4 - 1

  = 3

b = $2m$

  = 2 * 2

  = 4