Question

8.A hydraulic lift has been constructed to lift vehicles of maximum 3000kgweight. The area of crosssection of the piston's platform on which thevehicles are lifted is 580sq cm. Calculate the maximum pressureexperienced on the small
piston.​

Answer 1

Answer:

Explanation:

It is given that,

The maximum weight of vehicle that can be lifted, m = 3000 kg

The area of crosssection of the piston's platform on which the  vehicles are lifted = 580 sq cm. = 580 * 10⁻⁴ m²

=> Thus, the maximum force applied by the load can be calculated by the following equation:

F = mg

= 3000 * 9.8

= 29400 N

=> Now, the max pressure applied on the piston:

p = FIA

= 29400 / 580 * 10⁻⁴

= 5.069 * 10⁵ pa.

Thus,  the maximum pressure  experienced on the small piston is 5.069 * 10⁵ pa.