8. A man throws a ball to maximum horizontal
distance of 80m.Calculate the maximumheight
reached
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2
Answer:
We know that R = u2 * Sin 2θ / g. So, 80 = u2 /g. Now, H = height reached by ball = u2 Sin2θ / 2g.
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Hey mate this is ur answer...Hope it will help you...:-)
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