Question

8
A paraglides jumps from an aeroplane. He falls down with
a Velody of 78 m/s. He opens his parachote in air and his
Velocity of falling decreased to 50 m/s, within 12 s. Find the
Force of air experienced on the paraglider if he weighs 50 kg.​

Answer 1

Answer

• The force experienced is 46 N

Explanation

Given

• Initial velocity = 78 m/s
• Final Velocity = 50 m/s
• Time = 12 sec

To Find

• Force that the paraglider experience

Solution

[So here we may first find the acceleration of the body using the first Equation of motion, and then using the Newton's second law will give us our final answer]

✭ Acceleration of the Paraglider

➝ v = u+at

➝ 50 = 78 + a×12

➝ 50-78 = 12a

➝ -28 = 12a

➝ -28/12 = a

➝ Acceleration = -2.3 m/s²

✭ Force Experienced

➝ F = ma

➝ F = 50 × 2.3

➝ F = 46 N

Answer 2

$\begin{lgathered}\begin{lgathered}\begin{lgathered}\tt {\pink{Given}}\begin{cases} \sf{\green{Initial\: velocity (u) = 78m/s}}\\ \sf{\blue{Final\: velocity (v) = 50m/s}}\\ \sf{\orange{Time (t) = 12sec}}\end{cases}\end{lgathered} \:\end{lgathered}\end{lgathered}$

$\large{\underline{\underline{To\: find}}}$

• Force experienced by the paraglider.

$\large{\underline{\underline{Solution}}}$

★ By using first equation of motion

$\underline{\boxed{v = u + at}}$

$\implies{ 50 = 78 + a(12)}$

$\implies{ 50 = 78 + 12a}$

$\implies{-12a = 78 - 50}$

$\implies{ -12a = 28}$

$\implies{ a = \dfrac{28}{-12}}$

$\implies{a = -2.3m/s^2 }$

★ Now, using Newton's second law

$\underline{\boxed{F = ma}}$

$\implies{F = 50 × (2.3) }$

$\implies{F = 46 N }$