Question

8. Ajinkya Rabane hits the ball witha force of 500N & the ball reached at boundary ins sec The ball covers the distance of 300m, what will be the power of Ajinkya Rahone?​

Answer 1

Valid question: Ajinkya Rahane hits the ball with a force of 500 Newton & the ball reached at boundary in 5 seconds. The ball covers the distance of 300 m, what will be the power of Ajinkya Rahane?

• Dear user I don't know what is the time given in this question but I am assuming that it is 5 seconds.

Provided that:

• Time = 5 seconds
• Distance = 300 metres
• Force = 500 Newton

To calculate:

• Power

Solution:

• Power = 30000 W

Using concepts:

• Power formula
• Work done formula

Using formulas:

• Power is given by the mentioned formula:

• ${\small{\underline{\boxed{\pmb{\sf{Power \: = \dfrac{Work \: done}{Time \: taken}}}}}}}$

• Work done is given by the mentioned formula:

• ${\small{\underline{\boxed{\pmb{\sf{Work \: done \: = Force \times Displacement}}}}}}$

Required solution:

~ Firstly let us calculate the work done by using suitable formula!

→ Work done = Force × Displacement

→ W = Fs

→ W = 500 × 300

→ W = 150000 Joules

→ Work done = 1,50,000 Joules

~ Now let us calculate the power!

$:\rightarrow \sf Power \: = \dfrac{Work \: done}{Time} \\ \\ :\rightarrow \sf Power \: = \dfrac{150000}{5} \\ \\ :\rightarrow \sf Power \: = 30000 \: Watts$

→ Power = 30000 W