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An AP consists of 50 terms of which 3rd
term is 12 and the last term is 106 .find the 29th term . please do it step by step . no direct answer .
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given : a3 =12 , n =50 , an = 106 , a29 = ?
a3=12
a+2d =12
a = 12-2d -1
an = a + (n-1) d
106 = 12-2d+ (50-1)d
106= 12 - 2d + 49d
106 = 12+47d
106-12= 47d
94= 47d
94/47=d
2= d
put in eq1
a= 12-2d
a= 12-2×2
a= 12-4=8
a29 = a + 28d
a29= 8+28×2
a29= 8+56
a29= 64
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