Question

8
An AP consists of 50 terms of which 3rd
term is 12 and the last term is 106 .find the 29th term . please do it step by step . no direct answer .​

Answer 1

given : a3 =12 , n =50 , an = 106 , a29 = ?

a3=12

a+2d =12

a = 12-2d -1

an = a + (n-1) d

106 = 12-2d+ (50-1)d

106= 12 - 2d + 49d

106 = 12+47d

106-12= 47d

94= 47d

94/47=d

2= d

put in eq1

a= 12-2d

a= 12-2×2

a= 12-4=8

a29 = a + 28d

a29= 8+28×2

a29= 8+56

a29= 64