Question

8. An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th
term​

Answer 1

Answer:

a+2d= 12. --(i)

a+2d= 12. --(i)a+49d= 106. --(ii)

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equation

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get d=2. a=8

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get d=2. a=8Now a and d is available so use the general formula of ap

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get d=2. a=8Now a and d is available so use the general formula of api.e,

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get d=2. a=8Now a and d is available so use the general formula of api.e,An=a+(n-1)d

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get d=2. a=8Now a and d is available so use the general formula of api.e,An=a+(n-1)da29=8+(29-1)2

a+2d= 12. --(i)a+49d= 106. --(ii)Now eliminates i and ii equationyou get d=2. a=8Now a and d is available so use the general formula of api.e,An=a+(n-1)da29=8+(29-1)2a29=8+56

a29 = 64

Answer 2

Answer:64

a+2d=12

a+49d=106

⇒47d=94

⇒d=2

a+4=12

⇒a=8

29th term : - 

a+28d=8+56=64