Question

8. An object is moving with constant acceleration. Its velocity is 48ms at the end of 10 second
and becomes 68ms at the end of 15 second. What would be the distance travelled by the
ubject in 15 second?​

Answer 1

Answer:

it may be possible this way....

Answer 2

Answer:

solved

Explanation:

68 = u + 15a

48 = u + 10a

a = 4 , u = 8

S = ut + at²/2

S = 15x8 + 4x15²/2 = 570 m.