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Ans. T
A ball thrown up vertically returns to the
thrower after 6s. Find the velocity with which it
was thrown up.
Please ans me fast
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Answer:
ball thrown up so total time in going up and comming down is 6 sec so time to only come down is 6÷2=3
now it returns to hand that means final velocity is 0
u that is initial velocity is to be find so apply 1st equation of motion
v=u+at here a is equal to minus of g
0=u-gt
u=gt
u=10×3
u=30 metre per sec
hope it helps,!
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