Question

8)
Calculate the molarity of the solution.
of 30ml of 0.5M H₂SO4 diluted to
500ml​

Answer 1

Answer:

Final molarity of solution is 3/100

Explanation:

Molarity can be simply calculated by equation of conservation of moles in dilution-

M1V1=M2V2

here, M1=0.5, V1=30ml and V2=500ml

Putting value in equation

0.5*30= 500*M2

15=500M2

15/500=M2

M2=3/100 M

M2=0.03M

hope it helps you!!!!

Answer 2

Answer:

Explanation:

Molarity of original solution (M)= n/V

Where n is the number of moles of solute ,

And V is the volume of solution

n = 0.5× 30/ 1000

^ we divided the product by 1000 to convert ml to l

n = 0.015 moles

The number of moles of solute does not change when diluted

New volume = V = original volume + volume

of water added

V= 530 ml = 530/1000

New molarity = M = n/V

= 0.015 × 1000/ 530

= 0.028 ~ 0.03 M