8 chairs and 5 tables for aclasdrom cost rupees 10500 while 5 chairs and 3 tables cost rupees 6450 find the cost of chairs and that of each tables
Answers
Answered by
79
Let the number of chairs be X
Let the number of tables be Y
According to the question,
8X + 5Y = 10500 —1
5X + 3Y = 6450 —2
Multiply equation 1 by 3 and equation 2 by 5
=> 24X + 15Y = 31500
25X + 15Y = 32250
(-) (-) (-)
_________________
-1X + 0 = -750
X = 750
putting value of X in equation 2
=> 5(750) + 3Y = 6450
3750 + 3Y = 6450
3Y = 6450 - 3750
Y = 2700/ 3
Y = 900
therefore, cost of 1 chair = Rs. 750 and cost of 1 table = Rs. 900
Let the number of tables be Y
According to the question,
8X + 5Y = 10500 —1
5X + 3Y = 6450 —2
Multiply equation 1 by 3 and equation 2 by 5
=> 24X + 15Y = 31500
25X + 15Y = 32250
(-) (-) (-)
_________________
-1X + 0 = -750
X = 750
putting value of X in equation 2
=> 5(750) + 3Y = 6450
3750 + 3Y = 6450
3Y = 6450 - 3750
Y = 2700/ 3
Y = 900
therefore, cost of 1 chair = Rs. 750 and cost of 1 table = Rs. 900
Answered by
31
Let the cost of a chair be ₹ x and that of a table be ₹ y. Then,
➡ 8x + 5y = 10500 -----1)
and,
5x + 3y = 6450 -------2)
➡ Multiply by 3 and 5 in eq. 1 and 2 respectively
➡ 24x + 15y = 31500
and,
25x + 15y = 32250
By using Elimination method, we get
x = 750
Put the value of x in equation 2
5(750) + 3y = 6450
3750 + 3y = 6450
3y = 6450-3750
3y = 2700
y = 900
Thus the cost of a chair is ₹ 750 and the cost of a table is ₹ 900
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