Question

8. Convert into mole.
(a) 12 g of oxygen gas
(b) 20 g of water
(c) 22 g of carbon dioxide.​

Answer 1

Answer:

mole - mass in grams / molicular mass

a) 12 /16 = 0.75mol

b) H2O = 18 - molicular mass

20/18 = 1,11

c ) CO2 - 44 - molicular mass

22 /44 = 0,5

Answer 2

Question :-

Convert into mole.

(a) 12 g of oxygen gas

(b) 20 g of water

(c) 22 g of Carbon dioxide.

Answer :-

(a) Given mass of oxygen gas = 12 g

Molar mass of oxygen gas (O2) = 32 g

Mole of oxygen gas 12/32 = 0.375 mole

(b) Given mass of water = 20 g

Molar mass of water (H2O) = (2 x 1) + 16 = 18 g

Mole of water = 20/18 = 1.12 mole

(c) Given mass of Carbon dioxide = 22 g

Molar mass of carbon dioxide (CO2) = (1 x 12) + (2 x 16)

= 12 + 32 = 44 g

∴ Mole of carbon dioxide = 22/44 = 0.5 mole

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