. 8. Determine two nearest number of smallest 5 digit number which are exactly divisible by 7,8 14 and 21.
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Smallest five digit number = 10000
Let us divide this by the L.C.M of 7, 11, 21
L.C.M of 7, 11, 21 = 231 (Refer Factoring - Least Common Multiple (LCM) - In Depth to calculate the LCM)
Dividing 10000 by 231 leaves a reminder 67 , Subtract 67 from 10000 = 9933
So this means 9933 is divisible by 231.
9933+231 = 10164 (which will also be divisible by 231, 7, 11 and 21)
To find the number which leaves reminder 5, we have to add 5 to 10164.
So the answer is 10169.
Step-by-step explanation:
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