Question

8. E is a point on the side AD produced of a
parallelogram ABCD and BE intersects CD
at F. Show that AABE- A CFB.​

Answer 1

In △ABE and △CFB,

∠ABE=∠CFB (Alternate angles)

∠BAE=∠BCF (opposite angles of a parallelogram)

∴ By AA criterion of similarity, △ABE ∼ △CFB