Question

8. Express 92 as the sum of two consecutive integers.

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Answer 1

Answer:

Let the first odd number be n

Let the first odd number be nThen the next odd number is n+2

Let the first odd number be nThen the next odd number is n+2=>n+n+2=92

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides2n+0=92-2

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides2n+0=92-22n=90

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides2n+0=92-22n=90Divide both sides by 2

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides2n+0=92-22n=90Divide both sides by 2n=90/2=45

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides2n+0=92-22n=90Divide both sides by 2n=90/2=45So the second odd number is 45+2=47

Let the first odd number be nThen the next odd number is n+2=>n+n+2=922n+2=92Subtract 2 from both sides2n+0=92-22n=90Divide both sides by 2n=90/2=45So the second odd number is 45+2=4745+47= 92

Answer 2

Answer:

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