(8) Factorise: 12(x+y)2-35-(x+y) *
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Answer:
let (x+y)=z
=> 12z²-z-35
=> 12z² -21z + 20z - 35
=> 3z(4z - 7) + 5(4z - 7)
=> (4z-7)(3z+5)
now substitute the value of z
=> [4(x+y) - 7][3(x+y) + 5]
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