Question

8. Find m if (m - 12)x2 + 2(m - 12) x + 2 = 0 has real and equal roots.​

Answer 1

Step-by-step explanation:

mx2-12x2+2mx-24x+2= 0

Answer 2

Step-by-step explanation:

$\sf (m-12){x}^{2} + 2(m-12)x +2 = 0 \\ \\ \sf For\:a\:quadratic \: equation\:to \:have \: real \:and\:equal \: roots \\ \\ \sf \Delta \: should \: be \: zero \\ \\ \sf \Delta = 0 \\ \\ \sf {b}^{2} - 4ac = 0 \\ \\ \sf {2(m-12)}^{2} - 4(m-12)×2 = 0 \\ \\ \sf 4{(m-12)}^{2} - 8(m-12)= 0 \\ \\ \sf 4(m-12)( m-12 - 2 ) = 0 \\ \\ \sf 4(m-12)(m-14)=0 \\ \\ \sf m = 12 , 14 \\ \\ \sf 12 \:is\:not\: accepted\:because \: coefficient \:of\:{x}^{2} \:becomes \:zero$

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