8. Find the area of a triangle with base 5 cm
and whose height is equal to that of a
rectangle with base 5 cm and area 20 cm
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Base = 5 cm
Area of ∆= 20cm
- 20cm = L×B
- 20cm = 5×B
- 20cm = B
5
4. 4cm = B
hence height of ∆= 4cm
- Area of ∆= 1/2 ×B×H
- = 1/2× 4cm ×5cm
- = 10 sq.cm.
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