Question

8. Find the breadth of that rectangle whose length is 45 m 50 cm and perimeter is 140 metres.
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Answer 1

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GiveN :-

$\displaystyle \sf \: length \: of \: rectangle \: = 45 m \: 50cm \\ \\ \sf= 45.5 m \: \\ \\ \sf \: perimeter \: = 140 \: meter$

To FinD :-

$\sf \: the \: width \: of \: the \: rectangle \: .$

SolutioN :-

Let the width of the rectangle is 'x'

$\sf \: peremeter \: of \: rectangle \: = 2(length \: + \: width) \\ \\ \sf \: 140 = 2(45.5 + x) \\ \\ \sf \: 140 = 91 + 2x \\ \\ \sf \: 2x = 140 - 91 \\ \\ \sf \: 2x = 49 \\ \\ \sf x = \frac{49}{2} \\ \\ \sf \: x = 24.5$

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So the width of the rectangle is 24.5 meter or 24m 50cm.

Answer 2

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Reffer to the attachment

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