Question

8. Find the coordinates of the point on x-axis which is equidistant from
the points (-2,5) and (2,-3).
[CBSE 2017]
TO
on the
borayic ach of yothich is at a distance of 10 units from​

Answer 1

Step-by-step explanation:

The point on x-axis, (x,0) be X.

End points are A(-2,5) and B(2,-3).

D=√(x2-x1)²+(y2-y1)²

By taking AX=BX:

√(x-(-2)²+(0-5)²=√(2-x)²+(-3-0)²

√x²+4+4x+25=√4+x²-4x+9

By squaring on both side:

x²+4x+29=x²-4x+13

x²-x²+4x+4x+29-13=0

8x+16=0

x=-16/8=-2.

The point on x-axis is (-2,0).

Answer 2

Answer:

answer attached in photo