Question

8. Find the gre.
20
9. Find the least number of five digits which is exactly divisible by 32,36 and 45
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Answer 1

9-First we have to find the LCM of 8,20 and 24

∴ LCM of given numbers =2×2××2×3×5=120

Greatest number of 3 digit is 999

We divide 999 by 120 and find the remainder

According to given condition , we need a greatest 3-digit number which is exactly divisible by 120

∴ The required number =999−39=960