Question

8. Find the greatest number of 5 digits which when divided by 25, 30 and 40
leaves a remainder of 20, 25 and 35 respectively.​

Answer 1

Answer:

So the smallest five- digit number divisible by 25, 30 and 40 is (600 x 17)=10200. Therefore the required number is= (10200–5)= 10195. This number will give a remainder of 20, 25 and 35 when divided by 25, 30 and 40 Respectively.