Question

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8. Find the image of the point (1, 2) in the straight line 3x + 4y - 1=0.​

Answer 1

Answer:

Step-by-step explanation:

(−75,−65)

(78,12)

(78,−12)

(−75,12)

Answer :

A

Solution :

Let (a, b) be the image of point (1, 2) w.r.t. line 3x+4y−1=0

∴(a+12,b+22) will be on the line 3x+4y−1=0

⇒3(a+12)+4(b+22)−1=0

⇒3a+3+4b+8−2=0

⇒3a+4b+9=0

Now, co-ordinates given in option 'a' satisfies the equation 3a+4b+9=0

Thus, the image of point (1, 2) is (−75,−65).