8. Find the principal amount for the rate of interest 10% p.a., time 3 years and compound interest earn
is 993.
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Answered by
2
Ci = p*r*t/100
993=x*10*3/100
993=30x/100
30x=993-100
30x=893
X=893/30
993=x*10*3/100
993=30x/100
30x=993-100
30x=893
X=893/30
Answered by
2
Answer:
Rate of interest, r = 10% =10010=0.1
Time period, t⇒3years.
number of times compounded yearly, n = 1.
compounded interest = Rs 993.
∴ Amount A = principal + compound interest
= P + 993.
we know, A =P(1+nr)nt
P+993=P(1+10.1)3
P+993=P(1.1)3
P+993=1.331P.
⇒993=1.331P−P
⇒0.33P=993.
⇒P=0.331993
⇒P=Rs3000
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