Math, asked by maheshurgunde, 4 months ago

8)Find the values of x and y in the following parallelogram.​

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Answers

Answered by rishi200572
12

Answer:

as the diagonals of a parallelogram bisect each other, then AO is equal to OC.

similarly DO is equal to OB.

Step-by-step explanation:

so,

x+8=16-x

x+x=16-8

2x=8

x=8/2

x=4

now,

2y+13=5y+4

2y-5y=4-13

-3y= -9

y= -9/-3

y= 3

therefore x is 4 and y is 3

Answered by amitnrw
7

Given : A parallelogram ABCD , O is the point of intersection of diagonals

AO = x + 8

CO = 16 - x

BO = 5y + 4

DO = 2y + 13

To Find: Value of x and y

Solution:

Diagonals of a parallelogram bisect each other

Hence  AO = CO  = AC/2

BO = DO = BD/2

AO = CO

=>  x + 8 = 16 - x

=> 2x = 8

=> x= 4

BO = DO

=> 5y + 4 = 2y + 13  

=> 3y = 9

=> y = 3

Hence x = 4  and y = 3  is the  required answer.

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