Question

8. Find the values of y for which the distance between the points P(2. - 3) and Q(10.) is
10 units.​

Answer 1

$\huge\mathfrak{\underline{\underline{\red{Answer:-}}}}$

Answer 2

Answer:

the formula to calculate the distance between two points (a,b) and (c,d) is given by

dist d = √(a-c)² + (b-d)²

applying it for this ques we have d=10 units

10 = √(2 - 10)² + (-3-y)²

squaring both sides

100 = (-8)² + (9 + y² + 6y)

100 = 64 +9 + y² + 6y

y² + 6y - 27 = 0

y² + 9y - 3y - 27 = 0

y(y + 9) -3(y + 9) = 0

(y-3)(y+9) = 0

y=3 or y=-9