Question

8. For each of two successive years, bean prices
rose by 10%. At the beginning of the first
year, 1 kg of bean cost $20. At the end of the
second year, how many grams of bean, to the
nearest ten grams could be bought for $50?​

Answer 1

Answer:

t the end of one year, the price of 1kg of beans is (1+10%)(20)

= 1.10*20 = 22

at the end of year 2, the price of 1kg o= 1.10*22 = 24.2

So we can purchase 1KG of beans for $24.20.

Solving for KG/dollar 1KG/24.20 = (1/24.2)KG/dollar

$50(1/24.2)= 2.066116KG = 2.0661 gram

f beans is (1+10%)(22)