8 g of helium and 4 g of hydrogen gas are present
in a closed vessel at 127°C. If pressure exerted by
the gas mixture is 4.1 atm then the volume of the
container is
[NCERT Pg. 145]
(1) 32 L
(2) 16 L
(3) 40 L
(4) 24 L
Answers
Answered by
7
Answer:
32 litre is the right answer
Answered by
11
Explanation:
- moles of he = 8/4 =2
- moles of h2 =4/2= 2
- pv=nrt
- v= 4 × 0.08 × 400 devided by 4.1
- =32L
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