8 identical coins are arranged in a row .the total number of ways in which the number of heads are equal to number of tails is?
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Since we need to have equal number of heads and tails
⇒ there must be 4 heads and 4 tails
Find the number of combinations to get 4 heads:
Number of combination = 8C4
Number of combination = (8 x 7 x 6 x 5) / ( 4 x 3 x 2 x 1)
Number of combination = 70
Answer: There are 70 ways
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