Why it is recommended to use a higher molar ratio than theoritical ratio of nabh4?
Answers
he problem with this, however, is the fact that we only started with .6 grams of ketone. There must have been a mistake made during recrystallization or after filtration, there was still a decent amount of water weight present. There should be no chance of a 200% yield, unless there was some other factor that made the weight of the crystals go up that much. By only starting with .6 grams of ketone, there should be no more than .6 grams of product due to their molar ratios. Also, the result of my IR was unsuccessful. Instead of getting distinct peaks from the IR spectroscopy, there was just one broad set of wavy lines. To distinguish that the product is indeed an alcohol, there should be a peak at approximately 3200-3600 cm-1 to show that there is a presence of an –OH group. Also there should be a slight peak around 1500 cm-1to show that the molecule is in fact aromatic. By no means should there be a peak around the 1700 cm-1range because that is where the presence of a carbonyl group shows up. Since the IR and percent yield were unsuccessful, so was the melting point. The melting point of 9-fluorenol should be around 153-154ºC, however, my melting point was approximately 153-154ºC. This shows that my sample contained some sort of impurity in it for it to make the melting point go higher than it really should. Overall, this lab was not successful. I performed the lab, but somewhere during that performance, something went horribly wrong, giving me inaccurate results in all categories.