Question

8. If 3 sin θ = 4 cos θ then sec θ = ?​

Answer 1

Answer:

Step-by-step explanation:

solution

3sinФ - 4cosФ=0

3sinФ=4cosФ

⇒ sinФ/cosФ=4/3

⇒ tanФ=4/3

⇒ tanФ=4/3

then the value of

tanФ=4/3

for 1 + tan²Ф=sec²Ф

⇒ 1 + 4/3=sec²Ф

⇒√ (3+4)/3=secФ

⇒ secФ=√7/3

for cosec²Ф=cot²Ф+1

⇒cosec²Ф=3/4+1

cosecФ=√7/4

Answer 2

Answer:

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Step-by-step explanation:

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