Question

8. If a, ß are the roots of x² – 3x + 2 = 0, then the equation with roots (a + 1), (B + 1) is
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Answer 1

hey buddy here is your answer

   x² – 3x + 2

=>x² -x- 2x + 2

=>x(x-1)-2(x-1)

=>(x-2)(x-1)

Hence the zeros of the polynomials are 1 and 2

hence A=1 and B=2

then,

     (A+1)(B+1)

=>(1+1)(2+1)

=>2*3

=>6

Hope it helps

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