Question

8. If two coconut trees 15 m and 25 m high are 70 m apart, then the height of the point of intersection of the line joining the top of each tree to the foot of the opposite tree is 0 に
(a)9 m (b) 9 20 m (0) (d) file m 56 56​

Answer 1

Step-by-step explanation:

perpendicular height =10m

distance between two coconut trees = 70m

by using Pythagoras theorem

h=√70² + 10²

h=√4900 +100

h= 70.7 m

Answer 2

Step-by-step explanation:

first of all

We know that in chapter triangle class 10

A formula is given that is

$1 \div x + 1 \div y = 1 \div z \\ see \: in \: rsagrawal \: book \: \\ now \: \: \\ 1 \div 25 + 1 \div 15 = 1 \div height \: of \: the \: point \: of \: intersection \\ \\ 3 + 5 \div 75 \\ 8 \div 75 \\ now \: reciprocal \: \\ height = 75 \div 8 = 9.375m$