8. In ДАВС, АВ = 8, find a and bif a + b = 32.
A
b
8
В
а
С
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Answer:
given AB=8
a+b=32
b=32_a...1
by Pythagoras theorem
b²=a²+8²
subsitude value b from eq. 1st
(32_a)²=a²+8²
32²+a²_64a=a²+8²
32²_64a=8²
64a=1024_64
64a=960
a=960÷64
a=15
from 1st eq.
b=32_a
b=32_15
b=17
a=15 &b=17
Explanation:
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