Question

8. In AABC, the bisector of angle B meets AC at D.
A line PQ || AC meets AB, BC and BD at P,
Q and R respectively.
Show that PR x BQ = QR BP.​

Answer 1

heya!

BP/BQ  = PR/PQ -- (equation 1)

AB/BC = AD/DC -- (equation 2)

PQ||AC So ΔBPQ ≈ ΔBAC

BP/BA = BQ/BC

BP/BQ = AB/BC --- (equation 3)

so from the equation 1 and equation 2 we can get this:

PR/RQ = AD/DC

thank u and hope it helps ! yay!