Question

8 In figure, if angle BAC=60' and BCA= 20' then find angle ADC

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Answer 1

Answer:

BAC+ BCA+ ABC = 180

Step-by-step explanation:

60+20+ ABC= 180.

ABC=180-80

100°

Answer 2

Step-by-step explanation:

<BAC = <ADC+<DCA (( exterior angle property ))

therefore <ADC = 30°

<DCA = 30°

checked

in ∆ABC

<B = 100° (( angle sum property))

<ADC = 30°

<DCB = 20°+30° = 50°

in ∆BCD

<B+<ADC+<DCB=180°

100°+30°+50° = 180°