Question

8. In new system, force, velocity and density are
considered as new fundamental quantities. The
dimensional formula of power in new system will be
(1) FVD'] (2) [FVD]
(3) [F VAD] 471F' VDO​

Answer 1

Hey Dear,

◆ Answer -

[P] = [FV]

◆ Explanation -

Let dimensional formula of power in new system be -

[P] = [F^x.V^y.D^z]

According to known dimensions,

[L2M1T-3] = [L1M1T-2]^x [L1T-1]^y [L-3M1]^z

[L2M1T-3] = [L^(x+y-3z).M^(x+z).T^(-2x-y)]

Comparing indexes,

x + y - 3z = 2

x + z = 1

-2x-y = -3

Solving these,

x = 1

y = 1

z = 0

Therefore, dimensions of power in new system be

[P] = [F1.V1.D0]

Thanks for asking...

Answer 2

Answer:

1

Explanation: