Question

8. In PQR, PR = 10 cm, QR = 4 cm and PL = 6 cm. P 6cm M 10cm 1 1 L 4cm R 0) Sind OM​

Answer 1

⇒QR=

QP

2

+PR

2

When,

QR=QM+MR

QM=x−1

MR=x−2

QR=

6

2

+9

2

=

36+81

QR=

117

=10.82

From Question:

x−1+x−2=10.82

2x−3=10.82

x=

2

13.82

⇒QR=6.91

Answer 2

Answer:

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