Question

-8 is zero of the polynomial X^2+ax-72 and x^2+10x+b.Find a and b find the other zeros of the polynomial ​

Answer 1

Answer:

P(x) =x^2 +10x+b

P(-8)=(-8)^2 +10*(-8)+b=0

64-80+b=0

-16+b=0

So, b=16

And, P(x)=x^2 +ax-72

P(-8)=(-8)^2 +a(-8)-72=0

64-8a-72=0

-8a=72-64

-8a=8

So, a=-1