Question

8 K square + 19 K - 27 equal to zero

Answer 1

Given :

8 k² + 19 k - 27 = 0

= > 8 k² + 27 k - 8 k - 27 = 0

= > k ( 8 k + 27 ) - 1 ( 8 k + 27 ) = 0

= > ( k - 1 )( 8 k + 27 ) = 0

Either :

k - 1 = 0

= > k = 1

Or :

8 k + 27 = 0

= > 8 k = - 27

= > k = - 27/8

ANSWER :

Either k = 1 or k = - 27/8

Answer 2

A/Q

8 k² + 19 k - 27 = 0

=> 8 k² + 27 k - 8 k - 27 = 0

=> k ( 8 k + 27 ) - 1 ( 8 k + 27 ) = 0

=> ( k - 1 )( 8 k + 27 ) = 0

or,

k - 1 = 0

= > k = 1

Or,

8 k + 27 = 0

= > 8 k = - 27

= > k = - 27/8

now,

Either k = 1 or k = - 27/8

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