Question

8 Liters are drawn off from a can filled with milk and it is then filled with water. This operation is
performed three more times. The ratio of the quantity of milk now left in the can to that of the total
mixture is 16 81. How much milk did the can hold originally?
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Answer 1

Answer:

24 litres

Step-by-step explanation:

x{(1-8/x) power 4} divided by x = 16/81

here,

x= total weight  of the container

solving,

we get x=24

Answer 2

Given:

8 Liters are drawn off from a can filled with milk and it is then filled with water. This operation is  performed three more times.

Solution:

Assume that the original quantity of is $x$ litters.

$\[\frac{{16}}{{81}} = {\left( {1 - \frac{8}{x}} \right)^4}\]$

$\[ \Rightarrow 1 - \frac{8}{x} = \frac{2}{3}\]$

$\[ \Rightarrow \frac{8}{x} = 1 - \frac{2}{3}\]$

$\[ \Rightarrow x = 24\]$

Hence, the original quantity of is 24 litters.