Question

8 men and 12 boys can complete a work in 10 days while 6 men and 8 boys complete it in 14 days.The time taken by one man alone to complete the work is​

Answer 1

Answer:

140 days

Step-by-step explanation:

Let work done by 1 man in 1 day be x and work done by 1 boy in 1 day be y.

So, total work done by 8men and 12boys in 10 days = 8*x*10 + 12*y*10 = 80x+120y

and, total work done by 6men and 8boys in 14 days = 6*x*14 + 8*y*14 = 84x+112y

So, 80x+120y = 84x+112y

4x=8y

x=2y

So, 8men and 6men(12boys) can do work in 10 days, means 14 men can do work in 10days, so 1 man can do the work in 14*10 = 140 days

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