8 men and 12 boys can finish a piece of work in 5 days while 6 men and 8 boys can finish it in 7 find the time taken by 1 man alone and that 1 boy alone finish the work
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Given...
Number of men =8
number of boy =12
take 5 days
While..
6 men and 8 boys
take 7 days ..
let the men =x
the boy = y
part of work by one men= x/7
part of work by one boy= y/12
equation is x/7+y/12= 1/5.....
.....eq(1)....
for other part........
part of work by a men =x/6
part of work by a boy= y/8
equation is x/6+y/8= 1/7.........this is
eq (2)......
solve eq (1)&(2) ....
x/8+y/12=1/5.......(1)
x/6+y/8=1/7.......(2)
solve both of the eq
then you will get
your answer
hope you like this....
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