Math, asked by Mister360, 3 months ago

8 men and 12 women finish work in 10 day while 6 women and 8 men can finish it in 14 days. Find the time taken by the one women alone that by one men alone to finish the work.

Answers

Answered by ItzMeMukku
25

\huge\purple{Solution:}

\huge\bold{Let:}

The time taken by 1 women be 1/X in 1day

The time taken by 1 man be 1/Y in day

\huge\bold{To Find}

Time taken by 1 women and man alone.

Given, 8 women and 12 men can together finish an embroiderywork in 10 days.

⇒8X+12Y=1/10-------(1)

Given,6 women and 8 men can finish it in 14 days.

⇒6X+8Y=1/14---------(2)

Now , solving equation 1 and 2 by multiplying than subtracting eachother.

in equation 1 multiplying by 1/6 and equation 2 multiplying by 1/8

⇒48X+72Y=1/10

⇒1/48X+1/64Y=1/14

BY solving we get,

⇒72Y-64Y=1/10-1/14

⇒8Y=7-5/70

⇒8Y=2/70

⇒4Y=1/70

⇒Y=1/280

Putting the value of Y=1/280 in EQ 1

⇒8X+12×1/280=1/10

⇒8X+3/70=1/10

⇒8X=1/10-3/70

⇒8X=7-3/70

⇒8X=4/70

\bold{\boxed{⇒X=1/140}}

\huge\bold{Hence}

The time taken by one woman to finish the work=280 days

The time taken by one man to finish the work=140 days

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Answered by TheDiamondBoyy
48

Answer:-

  • The time taken by 1 woman alone to finish the work = 140 days
  • 1 man alone to finish the work = 280 days

step-by-step solution:-

Let,

  • 1 woman finish the work in X days
  • 1 man finish the work in Y days

Now,

  • Work done by 1 woman in 1 day = 1 / X
  • Work done by 1 man in 1 day = 1 / Y

1st Part:-

  • 8 women and 12 men finish work in 10 days ( Given )
  • 1 day work of 8 women and 12 men = 1 / 10 of total work

Now,

  • → 8/X + 12/Y = 1/10
  • → 4 ( 2/X + 3/Y ) = 1/10
  • → 2/X + 3/Y = 1/40

2nd Part:-

  • 6 women and 8 men finish work in 14 days ( Given )
  • 1 day work of 6 women and 8 men = 1 / 14 of total work

Now,

  • → 6 / X + 8 / Y = 1 / 14
  • → 2 (3 / X + 4 / Y ) = 1 / 14
  • → 3 / X + 4 / Y = 1 / 28

Now,

Putting 1/X = p and 1/Y = q in Part 1st & 2nd

  • → 2p + 3q = 1 / 40--------- ( 1 )
  • → 3p + 4q = 1 / 28---------- ( 2 )

Multiply equation 1 by 2 and equation 2 by 1

  • → 8p + 12q = 4 / 40
  • → 8p +12q = 1 / 10--------- ( 3 )
  • → 9p + 12q = 3 / 28-------- ( 4 )

On subtracting equation 3 and 4

  • → 8p +12q = 1/10
  • → 9p + 12q = 3/28

Calculation :-

  • → - p = 1 / 10 - 3 / 28
  • → -p = ( 14 - 15 ) / 140
  • → -p = -1 / 140
  • → p = 1 / 140

Now,

Substituting p= 1 / 140 in equation 3

  • → 8p +12q = 1 / 10
  • → 8 ( 1 / 140 ) +12q = 1 / 10
  • → 8 / 140 + 12q = 1 / 10
  • → 12q = 1 / 10 - 2 / 35
  • → 12q = ( 7 - 4 ) / 70
  • → 12q = 3 / 70
  • → q = 3 / ( 70 × 12 )
  • → q = 1 / ( 70 × 4 )
  • → q = 1 / 280

Now,

  • → p = 1 / 140 = 1 / X

So,

  • → Y = 140
  • q = 1 / 280 = 1 / Y
  • Y = 280

Therefore, The time taken by

1 woman alone to finish the work = 140 days

1 man alone to finish the work = 280 days

_____________________________________

✪✪ Hence Answered ✪✪

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