Question

8 men and 20 boys working 10 hours a day can do a peice of work in 60 days if a man's work is equal to that of 2 boys then how many boys will be required to helf 19 men to do twice the work in 50 days working 9 hours a day please tell ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Let x boys be required

1M=2B

therefore, (8*2)B + 20B(36B) working 10 hours do in 60 days. Take this as Work = 1(W1)

then, xB+(19*2)B (38+x)B working 9 hours do in 50 days. Take this work=2(W2)

Using,M1 D1 T1/W1 = M2 D2 T2/W2

substitute: 36*60*10/1 = (38 +x) *50*9/2

(38+x) = 36*60 10 *2/50*9

after simplifying: 38+x=96

x=96-38

therefore, 58 boys are required

hope this answer was helpful..= )