Math, asked by tejaswi1404, 11 months ago

8 men can complete a peice of work in 20 days. 8 women can complete a piece of work in 32 dats. in how mang days will 5 men and 8 women together complete the same work​

Answers

Answered by Kunal0154
1

Answer:

No Need it's already completed.

Answered by SauhardyaHaldar
1

Answer:

16 days

Step-by-step explanation:

The answer for this question is,

8×20 men = 8×32 women

5 men = 8 women

5 men + 8 women + 16 women

M1 D1 = M2 D2

8×32=16×D2

D2 8×32/16 = 16 days

(or)

8 men can complete a piece of work in 20 days

=> 1 man can complete the work in 20*8 = 160 days

=> work done by 1 man in 1 day = 1/160

Similarly, 8 women can complete the same work in 32 days

=> 1 woman can complete the work in 32*8 = 256 days

=> work done by 1 woman in 1 day = 1/256

Let 5 men and 8 women together complete the same work in x days

Work done by 5 men in x days = 5x/160 = x/32

Work done by 8 women in x days = 8x/256 = x/32

x/32 + x/32 = 1

x/16 = 1

x = 16

Required number of days = 16

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