Question

8 men can do a work in 12 days.in how mays days 6 men can do another piece of work which is 4 times the first work?

Answer 1

$\textsf{let 1 men does 1 unit of work per day}$

$<u><b>Total work:</u></b>$ 8×12=96units

$\textsf{6 days work of 8 men}$

8×6=48 units.

work left =96−48=48 units

After 6 days 4 men join. so total men is 12 men (8+4) they will do 12 unit of work per day

Now,

remaining work completed in

= $\dfrac{48}{12}$

= $\boxed{\boxed{\bold{4\: days}}}$