Math, asked by aakansha566, 8 months ago

8. Mr. Sharma borrowed a certain sum of money at 10% per annum compounded annually. If by paying 19,360 at the end of the second year and 31,944 at the end of the third year he clears the debt; find the sum borrowed
him.​

Answers

Answered by cutebrainlyteacher72
1

Let the term borrowed by Mr. sharma =xat 10%per annum for 2 yearsAmount =x(1+ 10010 ) 2 = 10121x

he than pays back 19360 Rs

⇒ Money left =

100

121x

−19360

Name with interest in 3rd year at 10% annum.

Amount =(

100

121x

−19360)(

10

11

)=31944

⇒(

100

121x

−19360)(

10

11

)=31944

100

121x

−19360=

11

31944×10

=29040

100

121x

=19360+29040=48400

⇒x=

121

48400×100

=40000 Rs

⇒ Sum borrowed =40000 Rs

Attachments:
Answered by zarasmith756
4

Answer:

Rs.= 4000

Step-by-step explanation:

At the end of the two years the amount is

A1 = P ( 1 + r/100 )n

= A1 = P ( 1 +  10/100 )2

Mr.Sharma payed Rs.19,360 at the end of the second year.

A2 = P ( 1 + r/100 )n

= 31,944 = ( P ( 1 + 10/100 )2  - 19,360 )  ( 1 + 10/100 )1

= 29040 = ( P ( 1 + 10/100 )2  - 19,360 )

=  ( P ( 1 + 10/100 )2 = 48,400

= P = Rs. 40,00

Mr.Sharma borrowed 40,000

Also F.Y.I   i  am 10 years old :)

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